Why Are MIM Parts 14-20% Smaller After Sintering?

A molded MIM green part is typically 118-122% of its final size. After sintering, it shrinks to 100%. This 14-20% linear shrinkage is not a defect — it is the direct result of densification from ~60% (powder packing density) to ~96-98% (sintered density).

The physics:

The green part contains metal powder at 55-65 vol% (the rest is binder). After debinding, the brown part is essentially a porous metal compact at ~60-65% density. During sintering, the particles fuse together and the pores shrink. The driving force is surface energy reduction — the particles want to minimize their surface area by bonding together.

The volume relationship:
  • If powder loading is 60 vol%, the green volume = final volume / 0.60 = 1.67× final volume (in 3D)
  • But because the binder is also present, the relationship is more complex
  • The 14-20% linear shrinkage corresponds to approximately 35-50% volume reduction
Why this is actually an advantage:
Aspect With 15-20% Shrinkage Without Shrinkage
Mold detail resolution Mold features are 1.18× larger — finer detail transferred to sintered part Mold features must be at final size
Surface finish Mold surface texture is relaxed 15-20% during sintering — smoother final surface No improvement from mold to part
Internal features Holes and cavities formed by larger, stronger core pins that can withstand higher injection pressure Smaller, weaker core pins needed
Dimensional tuning Shrinkage factor can be adjusted by ±1% to fine-tune final dimensions No tuning available
Quick Q: Why do MIM parts shrink 14-20%?

MIM parts shrink because the green part is only 55-65% metal powder by volume (the rest is binder). During sintering, the binder is removed and the metal particles densify to 95-99% density. The 14-20% linear shrinkage corresponds to a volume reduction of approximately 35-50%. This shrinkage is predictable and compensated for in the mold design — the mold cavity is made 1.16-1.20× larger than the final part size.

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Contact: Cindy